CUET General Test Question Paper 2024
| 41. | The difference of the greatest and the smallest of the fractions 1/2, 8/11, 7/8, 7/9, 5/6 is: |
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A. 3/8
B. 6/7
C. 7/9
D. 1/3
View Answer Discuss Work SpaceAnswer: option a
Explanation:
Converting all fractions to a common denominator, the greatest fraction is 7/8 and the smallest is 1/2. Their difference is 3/8.
| 42. | The sum of LCM and HCF of two numbers is 854. If the LCM is 60 times the HCF and one of the numbers is 70, then the other number is: |
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A. 160
B. 164
C. 168
D. 172
View Answer Discuss Work SpaceAnswer: option c
Explanation:
Let HCF = x, then LCM = 60x. Using the formula (LCM + HCF = 854), solve for x and the other number.
| 43. | The present age of Harish is 8 times the sum of the ages of his two sons at present. After 8 years, his age will be 2 times the sum of the ages of his two sons. The present age of Harish (in years) is: |
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A. 31
B. 32
C. 33
D. 34
View Answer Discuss Work SpaceAnswer: option b
Explanation:
Let the present age of Harish's sons be x. Using the given conditions, solve to find Harish’s current age as 32 years.
| 44. | In an examination, it is required to get 300 marks to pass. A student gets 225 marks and is declared fail by 10% marks. What are the maximum marks of the examination? |
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A. 700
B. 750
C. 800
D. 850
View Answer Discuss Work SpaceAnswer: option b
Explanation:
If failing by 10% means the student missed 75 marks, 10% of total marks equals 75. Solving gives total marks = 750.
| 45. | In a class of 40 students, the ratio of boys and girls is 3:2, and the average marks scored by boys is 42, and that by girls is 46. Then the average marks scored by the whole class is: |
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A. 43.4
B. 43.6
C. 43.8
D. 44
View Answer Discuss Work SpaceAnswer: option b
Explanation:
Using the weighted average formula: Average = [(24 x 42) + (16 x 46)] / 40 = 43.6