Inheritance in Java

Inheritance in Java - Important Points

26.		Which type of inheritance is used in Java for classes?

A. Single inheritance

B. Multiple inheritance

C. Hybrid inheritance

D. Hierarchical inheritance

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Answer: option a

Explanation:

Single inheritance is used in Java for classes.

27.		Which of the following is not a benefit of inheritance in Java?

A. Code reusability

B. Polymorphism

C. Encapsulation

D. Modularity

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Answer: option c

Explanation:

Encapsulation is not a benefit of inheritance in Java, as it is a separate concept.

28.		What is the access modifier of a method or field that is inherited by a subclass in Java?

A. public

B. private

C. protected

D. default

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Answer: option c

Explanation:

The access modifier of a method or field that is inherited by a subclass in Java is 'protected'.

29.		What is the output of the following program? class A { void display() { System.out.println("Class A"); } } class B extends A { void display() { System.out.println("Class B"); } } public class Main { public static void main(String[] args) { A obj = new B(); obj.display(); } }

29.

What is the output of the following program?

class A {
void display() {
System.out.println("Class A");
}
}
class B extends A {
void display() {
System.out.println("Class B");
}
}
public class Main {
public static void main(String[] args) {
A obj = new B();
obj.display();
}
}

A. Class A

B. Class B

C. Compilation error

D. Runtime error

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Answer: option b

Explanation:

The output of the above code will be 'Class B', as the 'display()' method in class B overrides the method in class A.

30.		What is the output of the following program? class A { int x = 10; } class B extends A { int x = 20; } public class Main { public static void main(String[] args) { A obj1 = new A(); B obj2 = new B(); System.out.println(obj1.x); System.out.println(obj2.x); } }

30.

What is the output of the following program?

class A {
int x = 10;
}
class B extends A {
int x = 20;
}
public class Main {
public static void main(String[] args) {
A obj1 = new A();
B obj2 = new B();
System.out.println(obj1.x);
System.out.println(obj2.x);
}
}

A. 10, 20

B. 20, 20

C. 10, 10

D. Compilation error

View Answer Discuss Work Space

Answer: option a

Explanation:

The output of the above code will be '10, 20', as the variable 'x' in class A and class B have different values.

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