LCM and HCF
LCM and HCF - Important Points
| 1. | The least number which when divided by 12, 27 and 35 leaves 6 as remainder, is: |
|---|
A. 3576
B. 7164
C. 7146
D. 4786
View Answer Discuss Work SpaceAnswer: option c
Explanation:
Number = LCM (12, 17, 35) + 6 = 7140 + 6 = 7146
| 2. | Find the smallest 3-digit number which when divided by 2, 3, 4 and 5 leaves a common remainder 3 but when divided by 9 leaves no remainder? |
|---|
A. 123
B. 153
C. 183
D. 213
View Answer Discuss Work SpaceAnswer: option b
Explanation:
| 3. | Four different coloured ropes of lengths 78 cm, 104 cm, 117 cm and 169 cm are to be cut into parts of equal length. Each part must be as long as possible. What is the maximum number of pieces that can be cut? |
|---|
A. 27
B. 33
C. 36
D. 42
View Answer Discuss Work SpaceAnswer: option c
Explanation:
Since each coloured rope must be cut into parts of equal length and each part must be as long as possible, so HCF should be taken to find out the longest rope.
=> HCF of 78, 104, 117, 169 = 13
Number of pieces from 78 cm rope = 78/13 = 6
Number of pieces from 104 cm rope = 104/13 = 8
Number of pieces from 117 cm rope = 117/13 = 9
Number of pieces from 78 cm rope = 169/13 = 13
Total number of pieces = 6 + 8 + 9 + 13 = 36.
| 4. | Find the greatest number which when divides 564 and 467 leaves the remainder as 4 and 7 respectively. |
|---|
A. 30
B. 20
C. 25
D. 35
View Answer Discuss Work SpaceAnswer: option b
Explanation:
| 5. | For which of the following number pair the product of their LCM and HCF is 48 and the difference of two numbers is 8? |
|---|
A. (1,48)
B. (6,8)
C. (4,12)
D. (3,16)
View Answer Discuss Work SpaceAnswer: option c
Explanation:
Let the numbers be 'a' and 'b'.
Product of two numbers = LCM x HCF = 48
=> ab = 48
Difference of two numbers = 8
=> a - b = 8
Factors of ab are (1,48) , (2,24), (3,16), (4,12) and (6,8).
Here, the only pair which satisfies the given condition is (4,12).
LCM and HCF Questions and Answers FAQ
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