Problems on Trains
Problems on Trains - Important Points
| 16. | A train 800 metres long is running at a speed of 78 km/hr. If it crosses a bridge in 1 minute, then the length of the bridge (in meters) is: |
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A. 130
B. 360
C. 500
D. 540
View Answer Discuss Work SpaceAnswer: option c
Explanation:
Given, Length of the train = 800 m
Speed of the train = 78 km/hr
= 78 * (5 / 18) m/s
= 390 / 18 m/s
Time to cross the bridge = 1 min = 60 sec
Distance = Speed * Time
=> Length of the train + length of the bridge = Speed of the train * Time to cross the bridge
=> 800 +length of the bridge = (390 / 18) * 60
=> 800 +length of the bridge = 23400 / 18
=> 800 +length of the bridge = 1300
=> length of the bridge = 1300 - 800 = 500 m
| 17. | A 1/4 mile long train travelling at a speed of 75 mph enters a tunnel 3 (1/2) miles long. How long does it take for the train to pass through the tunnel from the moment the front enters to the moment the rear emerges? |
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A. 2.5 min
B. 3 min
C. 3.2 min
D. 3.5 min
View Answer Discuss Work SpaceAnswer: option b
Explanation:
Total distance covered = ( 7/2 + 1/4 ) miles
= 15/4 miles.
Therefore, Time taken = ( 15 / 4 x 75 ) hrs
= 1 / 20 hrs
= ( 1/20 x 60 ) min
= 3 min
| 18. | A 110 metres long train is running with a speed of 60 kmph. In what time will it will pass a man running at 6 kmph in the direction opposite to that of train? |
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A. 5 sec
B. 6 sec
C. 7 sec
D. 10 sec
View Answer Discuss Work SpaceAnswer: option b
Explanation:
Speed of train relative to man = (60 + 6) km/hr = 66 km/hr = ( 66 x 5 /18 m/sec = (55 / 3 ) m/sec
Therefore, Time taken to pass the man = ( 110 x 3/55 ) sec = 6 sec
| 19. | Two trains 140 m and 160 m long, run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time (in seconds) which they take to cross each other, is: |
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A. 9
B. 9.6
C. 10
D. 10.8
View Answer Discuss Work SpaceAnswer: option d
Explanation:
Relative speed = (60 + 40) km/hr
= ( 100 x 5/18) m/ sec
= ( 250/9 ) m/sec
Distance covered in crossing each other = (140 + 160) m
= 300 m.
Required time = ( 300 x 9/250 ) sec
= 54 sec
= 10.8 sec
| 20. | Two trains, each 100 m long, moving in opposite directions, cross each other in 8 seconds. If one is moving twice as fast the other one, then the speed of the faster train is: |
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A. 30 km/hr
B. 45 km/hr
C. 60 km/hr
D. 75 km/hr
View Answer Discuss Work SpaceAnswer: option c
Explanation:
Given, Length of each train = 100 m
=> Sum of length of two trains = 100 + 100 = 200 m
Time taken by the trains to cross each other = 8 sec.
Let the speed of the slower train be x m/sec.
Then, speed of the faster train = 2x m/sec.
(Since, two trains are moving in opposite direction, Speed can be added)
Relative speed = speed of the slower train + speed of the faster train
= (x + 2x) m/sec
= 3x m/sec.
Relative speed =Sum of length of two trains / Time taken by the trains to cross each other
=> 3x = (100 + 100) / 8
=> 3x = 200 / 8
=> x = 200/ (8*3) m/sec
=> x = (200 / 24) m/sec
=> x = 50/6 m/sec
Speed of faster train = 2x
= 2 * 50/6
= 100/6 m/sec
---> Converting into km/hr
= 100/6 * (18 /5) km/hr
= 60 km/hr
Therefore,Speed of faster train = 60 km/hr
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